4x+8/x^2+2x

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Solution for 4x+8/x^2+2x equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+2*x+8/(x^2) = 0

6*x+8*x^-2 = 0

2*x*(4*x^-3+3) = 0

4*x^-3 = -3 // : 4

x^-3 = -3/4

-3 < 0

1/(x^3) = -3/4 // * x^3

1 = -3/4*x^3 // : -3/4

-4/3 = x^3

x^3 = -4/3 // ^ 1/3

x = -(4/3)^(1/3)

2*x = 0

2*x = 0 // : 2

x = 0

x in { 0} 

x = -(4/3)^(1/3)

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